Soi c\u1ea7u K\u1eb9p K\u00ecm ch\u00ednh x\u00e1c 100%<\/strong> m\u1edbi nh\u1ea5t hi\u1ec7n nay \u2013 \u00c1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u m\u1edbi nh\u1ea5t th\u1ef1c hi\u1ec7n soi c\u1ea7u l\u00f4 b\u1ea1ch th\u1ee7. Ch\u00fang t\u00f4i \u0111\u00e3 th\u1ef1c hi\u1ec7n ch\u00ednh x\u00e1c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y v\u00e0 ho\u00e0n to\u00e0n d\u1ef1a v\u00e0o x\u00e1c su\u1ea5t. Mang l\u1ea1i k\u1ebft qu\u1ea3 v\u00f4 c\u00f9ng vi\u00ean m\u00e3n<\/p>\n Ph\u1ea3i n\u00f3i th\u00eam r\u1eb1ng, ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 t\u1ef7 l\u1ec7 ch\u00ednh x\u00e1c v\u00f4 c\u00f9ng cao. \u0110\u01b0\u1ee3c admin \u00e1p d\u1ee5ng th\u01b0\u1eddng xuy\u00ean trong vi\u1ec7c ch\u1ed1t s\u1ed1 gi\u1edd v\u00e0ng h\u00e0ng ng\u00e0y. Tin r\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y s\u1ebd lu\u00f4n c\u00f3 m\u1eb7t trong s\u1ed5 soi c\u1ea7u l\u00f4<\/strong> c\u1ee7a anh em.<\/p>\n Ph\u1ea7n \u0111\u1ea7u ti\u00ean n\u00e0y ch\u00fang ta s\u1ebd c\u00f9ng t\u00ecm hi\u1ec3u xem nguy\u00ean l\u00fd th\u1ef1c hi\u1ec7n ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u k\u1eb9p k\u00ecm nh\u01b0 th\u1ebf n\u00e0o. Anh em h\u00e3y n\u1eafm v\u1eefng l\u00fd thuy\u1ebft n\u00e0y \u0111\u1ec3 th\u1ef1c hi\u1ec7n cho ch\u00ednh x\u00e1c.<\/p>\n Th\u1ed1ng k\u00ea trong 10 ng\u00e0y xem s\u1ed1 l\u1ea7n \u0110\u1ea7u, \u0110u\u00f4i v\u00e0 T\u1ed5ng n\u00e0o ra s\u1ed1 l\u1ea7n th\u1ea5p nh\u1ea5t v\u00e0 xu\u1ea5t hi\u1ec7n 21 l\u1ea7n tr\u1edf xu\u1ed1ng.<\/p>\n Gi\u1ea3i th\u00edch: L\u00fd do ch\u00fang ta th\u1ed1ng k\u00ea 21 l\u1ea7n tr\u1edf xu\u1ed1ng l\u00e0 v\u00ec trung b\u00ecnh m\u00f5i ng\u00e0y xu\u1ea5t hi\u1ec7n 2,7 l\u1ea7n (\u0111\u1ea7u, t\u1ed5ng ho\u1eb7c \u0111u\u00f4i). N\u00ean 10 ng\u00e0y l\u00e0 27 l\u1ea7n, v\u00ec v\u1eady ch\u00fang ta ch\u1ecdn 21 l\u1ea7n l\u00e0 s\u1ed1 l\u1ea7n th\u1ea5p nh\u1ea5t m\u00e0 chu\u1ea9n nh\u1ea5t.<\/p>\n Tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t: S\u1ebd lo\u1ea1i \u0111\u1ea7u (\u0111\u1ea7u, t\u1ed5ng) khi c\u00f3 2 \u0111\u1ea7u (\u0111u\u00f4i, t\u1ed5ng) tr\u1edf n\u00ean m\u00e0 c\u00f3 s\u1ed1 l\u1ea7n b\u00e9 nh\u1ea5t c\u00f9ng xu\u1ea5t hi\u1ec7n l\u00e0 21 l\u1ea7n. (chi ti\u1ebft ph\u1ea7n 2 n\u00f3i r\u00f5 h\u01a1n)<\/p>\n Gh\u00e9p c\u00e1c \u0110\u1ea7u, \u0110u\u00f4i, T\u1ed5ng \u0111\u1ec3 t\u00ecm ra c\u00e1c L\u00f4 c\u00f3 kh\u1ea3 n\u0103ng n\u1ed5. B\u00ean c\u1ea1nh \u0111\u00f3, lo\u1ea1i L\u00f4 c\u00f3 t\u1ed5ng s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n (\u0111\u1ea7u + du\u00f4i + t\u1ed5ng) tr\u00ean 70 l\u1ea7n.<\/p>\n V\u00ed d\u1ee5 \u00e1p d\u1ee5ng:<\/strong><\/p>\n Ch\u00fang ta \u0111\u00e3 t\u00ecm \u0111\u01b0\u1ee3c \u0110\u1ea7u s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n b\u00e9 nh\u1ea5t l\u00e0 \u0111\u1ea7u 5 = 21 l\u1ea7n, \u0110u\u00f4i s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n b\u00e9 nh\u1ea5t l\u00e0 \u0111u\u00f4i 3=20 l\u1ea7n, T\u1ed5ng s\u1ed1 l\u1ea7n ra b\u00e9 nh\u1ea5t l\u00e0 t\u1ed5ng 6= 19 l\u1ea7n.<\/p>\n D\u1eef ki\u1ec7n ph\u1ee5:<\/strong> T\u1ed5ng 8 xu\u1ea5t hi\u1ec7n = 30 l\u1ea7n, \u0110u\u00f4i 1 xu\u1ea5t hi\u1ec7n = 23 l\u1ea7n. \u0110\u1ea7u 3 xu\u1ea5t hi\u1ec7n = 24 l\u1ea7n.<\/p>\n Nh\u01b0 v\u1eady ta t\u00ecm \u0111\u01b0\u1ee3c l\u00f4 51<\/strong>, 33<\/strong> l\u00e0 c\u00e1c l\u00f4 c\u00f3 kh\u1ea3 n\u0103ng cao \u0111\u1ec3 \u0111\u00e1nh.<\/p>\n Ch\u00fa \u00fd:<\/strong> C\u1ea7u \u0111\u1eb9p l\u00e0 l\u00f4 \u0111\u00f3 c\u00f3 t\u1ed5ng <=63<\/strong>. T\u1eeb 64 \u0111\u1ebfn 70 l\u00e0 c\u1ea7u trung b\u00ecnh.<\/p>\n Anh em c\u1ea7n l\u1ef1a ch\u1ecdn ra 2 l\u00f4 trong c\u00e1c l\u00f4 c\u00f3 kh\u1ea3 n\u0103ng cao v\u00e0 tr\u00e1nh l\u00f4 gan v\u00e0 l\u00f4 v\u1eeba m\u1edbi ra \u0111\u1ec3 \u0111\u00e1nh: (tr\u00e1nh c\u00e1c l\u00f4 gan t\u1eeb 10 ng\u00e0y tr\u1edf l\u00ean v\u00e0 l\u00f4 v\u1eeba m\u1edbi ra)<\/em><\/p>\n Tr\u01b0\u1eddng h\u1ee3p 1:<\/strong> N\u1ebfu ch\u1ec9 c\u00f3 2 l\u00f4 ph\u00f9 h\u1ee3p b\u01b0\u1edbc 3. Ta \u0111\u00e1nh 2 l\u00f4 \u0111\u00f3 trong 3 ng\u00e0y. Ch\u1ec9 \u0111\u00e1nh Max l\u00e0 3 ng\u00e0y.<\/p>\n Tr\u01b0\u1eddng h\u1ee3p 2:<\/strong> N\u1ebfu ch\u1ec9 1 l\u00f4 th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n b\u01b0\u1edbc 3. Th\u00ec ta tr\u00e1nh l\u00f4 \u0111\u00f3 n\u1ebfu gan t\u1eeb 7 ng\u00e0y tr\u1edf l\u00ean. V\u00e0 l\u00f4 \u0111\u00f3 t\u1ed5ng s\u1ed1 l\u1ea7n xu\u1ea5t hi\u1ec7n <=63. Anh em s\u1ebd \u0111\u00e1nh b\u1ea1ch th\u1ee7 \u0111\u00f3 trong 6 ng\u00e0y.<\/p>\n Tr\u01b0\u1eddng h\u1ee3p 3:<\/strong> C\u00f3 nhi\u1ec1u h\u01a1n 2 l\u00f4 th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n b\u01b0\u1edbc 3. Ta ph\u1ea3i ch\u1ecdn ra 2 l\u00f4 \u0111\u00e1nh trong 3 ng\u00e0y.<\/p>\n Tr\u00fang \u00edt nh\u1ea5t 1 l\u00f4 th\u00ec d\u1eebng nu\u00f4i. V\u00ed d\u1ee5 v\u1ec1 t\u1eebng tr\u01b0\u1eddng h\u1ee3p anh em s\u1ebd xem \u1edf ph\u1ea7n 2.<\/p>\n1. Nguy\u00ean l\u00fd soi c\u1ea7u k\u1eb9p k\u00ecm ch\u00ednh x\u00e1c<\/span><\/h3>\n
B\u01b0\u1edbc 1: T\u00ecm hi\u1ec3u nguy\u00ean l\u00fd<\/strong><\/span><\/h4>\n
B\u01b0\u1edbc 2: Th\u1ef1c hi\u1ec7n gh\u00e9p c\u1ea7u<\/span><\/h4>\n
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B\u01b0\u1edbc 3: L\u1ef1a ch\u1ecdn c\u1ea7u \u0111\u1eb9p<\/span><\/h4>\n
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